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position() is not a property of a node, it is a property of an iteration over a sequence. So, I'm using nested for-each: <xsl:for-each select="report/section"> <xsl:number How can I get the index (position) of the superior loop?position represents the position of the item with a paticular title. . (The reason I say it's arguable is that I can see someone Feb 26, 2007 The fn:position function returns an integer representing the position (starting with 1, not 0) of the current context item within the context . Jul 15, 2014 <xsl:template match="/"> <test> <xsl:for-each select="root/element3"> <xsl:variable name="parent-position" select="position()" /> <xsl:variable Dec 15, 2014 You can use a variable here <xsl:for-each select="tagA"> <xsl:variable name="tagAPosition" select="position()"/> <xsl:value-of Feb 21, 2013 <script type="text/javascript"> // Always returns false console. So it's reasonable that xslt position function. Since each is the first 'country' child of its parent 'item', both get position()=1. <xsl:for-each-group select="item" group-adjacent="data[@name='title']"> if the current position is smaller than "5" <xsl:for-each select="$currentPage/descendant::node"> <xsl:if test="position() &lt;= 5"> </xsl:if> Mar 24, 2006 I have multiple xsl:for-each loops where I am trying to output the position of my index in each loop. thanks <xsl:template name="home-banner"> <xsl:for-each the first value is empty and so position() is not good enough (as below) Since there is no way to store local variables in xslt nor can I find hints of how to skip the first element in an XML string, when parsing it with XSLT for-each? use the conditional, and the position function. That said, here is a for-each select="listitem[position() > 1]" File: Data. xml <?xml version="1. <xsl:for-each select="Item[ItemType='BOOK']"> <xsl:if the returned list, we only want the first item, so we need to use the position() function. <xsl:for-each select="stuff"> <xsl:variable name="stuffcount" select="count()"/> <xsl:variable name="stuffpos" select="position() - 1"/> <xsl:for-each Dec 10, 2005 XSLT has the built-in ability to loop through data. These xsl:for-each loops are NOT nested. use position() to get loop index -->May 28, 2011 Can any one please tell how to select a data of a particular position using xslt. You create an XSLT loop with the <xsl:for-each> tag. Feb 11, 2008 @country is a property of a node. log("Dynamic position " + <xsl:value-of select="position()" /> + " IsDefault: " + Nov 21, 2012 As mentioned by @IanRoberts, it is difficult to give targeted assistance without seeing what your existing XSLT looks like. 0"?> <list xml:lang="en"> <title>title 1</title> <listitem>item 1</listitem> <listitem>item Processing Nodes by Position Problem You want to process nodes in a <xsl:for-each select="*[position( ) mod 3 = 1]"> <xsl:apply-templates select="